document.write( "Question 1115482: Roll a pair of fair dice? Then, find the probability to get sum on the top surfaces is less than seven or an odd number? \n" ); document.write( "
Algebra.Com's Answer #730356 by ikleyn(52873)\"\" \"About 
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Roll a pair of fair dice. Then, find the probability to get a sum on the top surfaces that is less than seven or an odd number.
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\n" ); document.write( "\n" ); document.write( "Less than 7: 2,3,4,5,6
\n" ); document.write( "Odd numbers: 3,5,7,9,11
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\n" ); document.write( "\n" ); document.write( "It is the union of these two sets: S= { 2,3,4,5,6,7,9,11 } that is of interest.
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\n" ); document.write( "\n" ); document.write( "To find the probability of getting a sum in S, we can look at S', the complement of S:
\n" ); document.write( "P(S) = 1-P(S')
\n" ); document.write( "S' = { 8, 10, 12 }
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\n" ); document.write( "\n" ); document.write( "There are 36 possible outcomes on the roll of two dice.
\n" ); document.write( "There are 5 ways to get an 8: {6,2}, {5,3}, {4,4}, {3,5}, {2,6}
\n" ); document.write( "There are 3 ways to get a 10: {4,6}, {5,5}, {6,4}
\n" ); document.write( "There is one way to get a 12: {6,6}
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\n" ); document.write( "\n" ); document.write( "In all, S' has 9 ways of occurring, so P(S') = 9/36, and P(S) = 1-9/36 = 3/4.
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\n" ); document.write( "\n" ); document.write( "Ans: P{sum = 2,3,4,5,6,7,9, or 11} = \"3%2F4\" = 75%.\r
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