document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115483>Question 1115483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose probability to support Hillary Clinton is 0.49. Then, in sample of 7 people, find the probability that all support Hillary? Exactly one person in a sample of 7 people who support Hillary? (joint event? think multiplication rule?) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730355 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730355\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use the binomial probability formula<BR>\n" );
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document.write( "Probability (P) (k successes in n trials) = nCk * p^k * (1-p)^(n-k), where nCk = n!/(k!*(n-k)!)<BR>\n" );
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document.write( "for this problem n=7 and p=0.49<BR>\n" );
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document.write( "P ( 7 people support Hillary out of 7 people) = 7C7 * (0.49)^7 * (1-0.49)^(7-7) = 0.0067<BR>\n" );
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document.write( "P (1 person supports Hillary out of 7 people) = 7C1 * (0.49)^1 * (1-0.49)^(7-1) = 0.0603<BR>\n" );
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