document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115433>Question 1115433</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help<BR>\n" );
document.write( "Given that the right triangle ABC as shown, fill in the values of tan &#952; and sec &#952;, and prove in general that 1 + tan^2 &#952; = sec^2 &#952;\r<BR>\n" );
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document.write( "Tan &#952; =_____<BR>\n" );
document.write( "Sec &#952;=_____\r<BR>\n" );
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document.write( "https://ibb.co/gdTOUH </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730292 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730292\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 + tan^2 = sec^2<BR>\n" );
document.write( "1 + sin^2/cos^2 = 1/cos^2<BR>\n" );
document.write( "Multiply by cos^2<BR>\n" );
document.write( "cos^2 + sin^2 = 1<BR>\n" );
document.write( "QED<BR>\n" );
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document.write( "Look up \"Half angle formulas\" on Wikipedia for more detail, if needed.<BR>\n" );
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