document.write( "Question 1115400: In a normal deck of 52 cards what is the probability that the card is
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document.write( "a) divisible by 3
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document.write( "b) a 7 of any suit or a diamond \n" );
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Algebra.Com's Answer #730270 by math_helper(2461) You can put this solution on YOUR website! In a normal deck of 52 cards what is the probability that \n" ); document.write( "a) divisible by 3 \n" ); document.write( "b) a 7 of any suit or a diamond \n" ); document.write( "====================================================\r \n" ); document.write( "\n" ); document.write( "a) divisible by 3: those are cards with rank 3, 6, or 9. Arguably one could include Q as well, it depends on the game. Many games treat all face cards as \"10\" but in games like poker, Q is greater than 10. \r \n" ); document.write( "\n" ); document.write( "Using 3,6, or 9 only: P(3,6,or 9) = 12/52 = \n" ); document.write( "Using 3,6,9, or Q: P(3,6,9, or Q) = 16/52 = \n" ); document.write( " \r \n" ); document.write( "\n" ); document.write( "b) There are four 7's and 13 diamonds: 4/52 + 13/52 = 17/52 \n" ); document.write( "However, the 7 of diamonds has been counted twice, so the answer is 17/52 - 1/52 = 16/52 = \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |