document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115220>Question 1115220</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My rectangular cabbage patch has a total area of 115 sq. ft. Find its perimeter in terms of the width x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730108 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730108\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> My rectangular cabbage patch has a total area of 115 sq. ft. Find its perimeter in terms of the width x.<BR>\n" );
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document.write( "P = 2L + 2x --- L = Length<BR>\n" );
document.write( "x*L = 115 --> L = 115/x<BR>\n" );
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document.write( "P = 2x + 230/x </SPAN>\n" );
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