document.write( "Question 1115187: Log 2 = 0.301 log 3 = 0.477 log 5 = 0.699 log 7 = 0.845\r
\n" ); document.write( "\n" ); document.write( "Using the information above\r
\n" ); document.write( "\n" ); document.write( "b) Log 5.25
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #730077 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
Log 2 = 0.301 log 3 = 0.477 log 5 = 0.699 log 7 = 0.845\r
\n" ); document.write( "\n" ); document.write( "Using the information above\r
\n" ); document.write( "\n" ); document.write( "b) Log 5.25
\n" ); document.write( "================
\n" ); document.write( "5.25 = 3*7/(2*2)
\n" ); document.write( "
\n" );