document.write( "Question 1115176: The bird capable of the fastest flying speed is the swift. A swift flying with the wind to a favorite feeding spot traveled 42 mi in 0.3 h. On returning, now against the wind, the swift was able to travel only 33 mi in the same amount of time. What is the rate of the swift in calm air, and what was the rate of the wind?
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Algebra.Com's Answer #730064 by mananth(16946)\"\" \"About 
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\n" ); document.write( "Bird speed= x km/h
\n" ); document.write( "wind speed= y km/h
\n" ); document.write( "with wind speed= (x+y)
\n" ); document.write( "against wind speed (x-y)
\n" ); document.write( "d= 42 with wind
\n" ); document.write( "42 / (x+y) = 0.3
\n" ); document.write( "divide by 0.3
\n" ); document.write( "140 / (x+y) = 1
\n" ); document.write( "(x+y) = 140 ............1
\n" ); document.write( "d= = 33 against wind
\n" ); document.write( "33/(x-y) = 0.3
\n" ); document.write( "divide by 0.3
\n" ); document.write( "110 /(x-y) = 1
\n" ); document.write( " x - y = 110 .............2
\n" ); document.write( "add up (1) & (2)
\n" ); document.write( "2 x = 250
\n" ); document.write( "/ 2
\n" ); document.write( "x= 125 mph speed of Plane in still air
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "we get y= 15 mph speed of wind
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