document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115138>Question 1115138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jack inherited $16,000 and invested it in two bonds that pay 6% and 8% annual interest.  At the end of one year the interest from the 8% bond was $580 greater than the interest from the 6%.  How much was invested in each bond? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #730050 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=730050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + y = 16,000 subtract y from both sides: x = 16,000-y<BR>\n" );
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document.write( "0.06x + 580 = 0.08y<BR>\n" );
document.write( "0.06x -0.08y = -580 substitute for x:<BR>\n" );
document.write( "0.06(16,000-y) - 0.08y = -580<BR>\n" );
document.write( "960-0.06y-0.08y = -580<BR>\n" );
document.write( "-0.14y = -1540<BR>\n" );
document.write( "y = 11,000<BR>\n" );
document.write( "$11,000 was invested at 8% and (16,000-11,000 = 5,000) $5,000 was invested at 6%<BR>\n" );
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document.write( "Check:<BR>\n" );
document.write( "11,000*0.08 = 880<BR>\n" );
document.write( "5,000*0.06 = 300<BR>\n" );
document.write( "and 880 - 300 = 580, so he made $580 more from the investment at 8%, just like the problem says.<BR>\n" );
document.write( " </SPAN>\n" );
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