document.write( "Question 1115137: Cindy invested $24,000 for one year, part at 6% and part at 9%. If the total amount of interest she earned was $1,740, how much money did he invest at each rate?
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Algebra.Com's Answer #730049 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 0.06x + 0.09(24,000-x) = 1,740 \n" ); document.write( "0.06x + 2160 - 0.09x = 1740 \n" ); document.write( "-0.03x = -420 \n" ); document.write( "x = 14,000 \n" ); document.write( "She invested 14,000 at 6% and 10,000 at 9% \n" ); document.write( "---------------------------------------------------- \n" ); document.write( "Check: \n" ); document.write( "14,000*0.06 = 840 \n" ); document.write( "10,000*0.09 = 900 \n" ); document.write( ". . . . . . .----- \n" ); document.write( "Total . . . $1,740 Correct \n" ); document.write( " |