document.write( "Question 1115137: Cindy invested $24,000 for one year, part at 6% and part at 9%. If the total amount of interest she earned was $1,740, how much money did he invest at each rate?
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Algebra.Com's Answer #730049 by addingup(3677)\"\" \"About 
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0.06x + 0.09(24,000-x) = 1,740
\n" ); document.write( "0.06x + 2160 - 0.09x = 1740
\n" ); document.write( "-0.03x = -420
\n" ); document.write( "x = 14,000
\n" ); document.write( "She invested 14,000 at 6% and 10,000 at 9%
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\n" ); document.write( "Check:
\n" ); document.write( "14,000*0.06 = 840
\n" ); document.write( "10,000*0.09 = 900
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\n" ); document.write( "Total . . . $1,740 Correct
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