document.write( "Question 1115126: please help me solve this.
\n" ); document.write( "Train A leaves a station traveling at 50 mph. Four hours later, train B leaves the same station traveling in the same direction at 60 mph. How long does it take for train B to catch up to train A?
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Algebra.Com's Answer #730026 by ankor@dixie-net.com(22740)\"\" \"About 
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Train A leaves a station traveling at 50 mph.
\n" ); document.write( " Four hours later, train B leaves the same station traveling in the same direction at 60 mph.
\n" ); document.write( " How long does it take for train B to catch up to train A?
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\n" ); document.write( "let t = B train's time when it overtakes A
\n" ); document.write( "then
\n" ); document.write( "(t+4) = A's train, time
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\n" ); document.write( "When B overtakes A, they will have traveled the same distance
\n" ); document.write( "Write distance equation; d = speed * time
\n" ); document.write( "B's dist = A's dist
\n" ); document.write( "60t = 50(t+ 4)
\n" ); document.write( "60t = 50t + 200
\n" ); document.write( "60t - 50t = 200
\n" ); document.write( "10t = 200
\n" ); document.write( "t = \"200%2F10\"
\n" ); document.write( "t = 20 hrs , B's travel time
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\n" ); document.write( "Check this, (A's time is 24 hrs) find the dist each travels
\n" ); document.write( "20 * 60 = 1200 mi
\n" ); document.write( "24 * 50 = 1200 mi
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