document.write( "Question 1115124: please help me solve this.
\n" ); document.write( "Train A leaves a station traveling at 40 mph. Six hours later, train B leaves the same station traveling in the same direction at 60 mph. How long does it take for train B to catch up to train A?
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Algebra.Com's Answer #730022 by addingup(3677)\"\" \"About 
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40x+(40*6) = 60x
\n" ); document.write( "40x+240 = 60x
\n" ); document.write( "240 = 20x
\n" ); document.write( "reverse the equation to have the unknown on the left:
\n" ); document.write( "20x = 240
\n" ); document.write( "x = 240/20 = 12
\n" ); document.write( "It will take train B 12 hours to catch up train A
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\n" ); document.write( "Check:
\n" ); document.write( "40x+(40*6) = 60x
\n" ); document.write( "40(12)+(40*6) = 60(12)
\n" ); document.write( "480+240 = 720 Correct
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