document.write( "Question 1115103: find the distance required for a car to reach a velocity of 80 ft/s when the acceleration is 20 ft/s^2 use the equation v= square root 2as, where v is the velocity, a is acceleration, and s is the distance \n" ); document.write( "

Algebra.Com's Answer #730008 by 4419875(21) $\"\"$ $\"About$

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S should be expressed in displacement not in distance since the problem is involved in a vector quantity. Anyway if this is meant by the problem and no direction is involved, as magnitude is indicated alone then, distance would be accepted for this case now.\r
\n" ); document.write( "\n" ); document.write( "we know that $\"v+=+sqrt%282as%29\"$ . We'll isolate s in the given formula.\r
\n" ); document.write( "\n" ); document.write( "1st - square both sides: $\"v%5E2+=+%28sqrt%282as%29%29%5E2\"$ which leaves us $\"v%5E2+=+2as\"$
\n" ); document.write( "2nd - divide both sides by 2a(we apply division PE) $\"%28v%5E2%29%2F2a+=+2as%2F2a\"$ \r
\n" ); document.write( "\n" ); document.write( "where $\"s+=+v%5E2%2F2a\"$ \r
\n" ); document.write( "\n" ); document.write( "3rd - Substitute $\"s+=+%28%2880ft%2Fs%29%5E2%29+%2F+%282%2820ft%2Fs%5E2%29%29\"$
\n" ); document.write( " $\"s+=+%286400+ft%5E2%2Fs%5E2%29%2F%2840ft%2Fs%5E2%29\"$ \r
\n" ); document.write( "\n" ); document.write( "s = 160 ft \n" ); document.write( "

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