document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1115039>Question 1115039</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the lengths of each side give the following right triangle:\r<BR>\n" );
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document.write( "Base=x<BR>\n" );
document.write( "HYPOTENUSE= x+8<BR>\n" );
document.write( "last side = 2x-8<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729955 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729955\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Use the Pythagorean Theorem<BR>\n" );
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document.write( "x^2 + (2x-8)^2 = (x+8)^2<BR>\n" );
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document.write( "x^2 + 4x^2-32x+64 = x^2+16x+64<BR>\n" );
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document.write( "5x^2-32x+64 = x^2+16x+64<BR>\n" );
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document.write( "4x^2-48x = 0<BR>\n" );
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document.write( "divide both sides of = by 4<BR>\n" );
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document.write( "x^2 -12x = 0<BR>\n" );
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document.write( "x(x-12) = 0<BR>\n" );
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document.write( "x = 0 or x = 12<BR>\n" );
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document.write( "we reject x = 0, since that means the base is 0 length and other side is negative length<BR>\n" );
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document.write( "base = 12, hypotenuse = 20, other side = 16<BR>\n" );
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document.write( "check answer<BR>\n" );
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document.write( "12^2 + 16^2 = 20^2<BR>\n" );
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document.write( "144 + 256 = 400<BR>\n" );
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document.write( "400 = 400<BR>\n" );
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document.write( "answer checks<BR>\n" );
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