document.write( "Question 1114997: Solve for the exact solutions over the interval (0°, 360°]
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\n" ); document.write( "\n" ); document.write( " \"+sec%5E2%28theta%29tan%28theta%29+=+2tan%28theta%29+\"
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Algebra.Com's Answer #729934 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"+sec%5E2%28theta%29tan%28theta%29+=+2tan%28theta%29+\"
\n" ); document.write( " \"+tan%28theta%29%28sec%5E2%28theta%29-2%29=0+\"
\n" ); document.write( "First part,
\n" ); document.write( "\"tan%28theta%29=0\"
\n" ); document.write( "\"theta=0\" and \"theta=180\"
\n" ); document.write( "Second part,
\n" ); document.write( "\"sec%5E2%28theta%29-2=0\"
\n" ); document.write( "\"sec%5E2%28theta%29=2\"
\n" ); document.write( "\"sec%28theta%29=0+%2B-+sqrt%282%29\"
\n" ); document.write( "\"cos%28theta%29=0+%2B-+1%2Fsqrt%282%29\"
\n" ); document.write( "\"cos%28theta%29=0+%2B-+sqrt%282%29%2F2\"
\n" ); document.write( "\"theta=%281%2F4%29pi\", \"theta=%283%2F4%29pi\", \"theta=%285%2F4%29pi\", and \"theta=%287%2F4%29pi\"
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