document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=100212>Question 100212</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diluting wine.<BR>\n" );
document.write( "A restuarant manager has 2 liters of white wine that is 12% alcohol. How many liters of white grape juice should be added to get a drink that is 10 % alcohol? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #72992 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=72992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of liters of white grape juice that needs to be added\r<BR>\n" );
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document.write( "(1)  The pure alcohol in the 2 liters of 12% alcohol is (0.12*2).<BR>\n" );
document.write( "(2)  The pure alcohol in the white grape juice is (0).<BR>\n" );
document.write( "(3)  The pure alcohol in the final mixture is (0.10(2+x))\r<BR>\n" );
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document.write( "Now we know that (1)+(2)=(3).  So our equation to solve is:\r<BR>\n" );
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document.write( "0.12*2=0.10(2+x)  get rid of parens and simplify<BR>\n" );
document.write( "0.24=0.20+0.10x  subtract 0.20 from both sides\r<BR>\n" );
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document.write( "0.24-0.20=0.10x  collect like terms\r<BR>\n" );
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document.write( "0.04=0.10x  divide both sides by 0.10\r<BR>\n" );
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document.write( "x=0.4 liter---number of liters of white grape juice that needs to be added\r<BR>\n" );
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document.write( "CK\r<BR>\n" );
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document.write( "0.12*2=0.10*2.4<BR>\n" );
document.write( "0.24=0.24\r<BR>\n" );
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document.write( "Hope this helps---ptaylor\r<BR>\n" );
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document.write( " </SPAN>\n" );
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