document.write( "Question 1114990: Find the equation of the straight line perpedicular to line y =x^ 2+ 1,and passing through the point (4,5). \r
\n" ); document.write( "\n" ); document.write( "What is the gradient of y = x^3/2,when x = 4? \n" ); document.write( "
Algebra.Com's Answer #729911 by stanbon(75887)\"\" \"About 
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Find the equation of the straight line perpendicular to line y =x^ 2+ 1,and
\n" ); document.write( " passing through the point (4,5).
\n" ); document.write( "slope of y = x^2+1 at every point = y' = 2x
\n" ); document.write( "slope of curve at x = 4 is 2*4 = 8
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\n" ); document.write( "slope of line perpendicular to the curve at (4,5) is -1/8
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\n" ); document.write( "Form:: y = mx + b
\n" ); document.write( "5 = (-1/8)4+b
\n" ); document.write( "b = 5+1/2 = 11/2
\n" ); document.write( "Equation:
\n" ); document.write( "y = (-1/8)x+(11/2)
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\n" ); document.write( "What is the gradient of y = x^3/2,when x = 4?
\n" ); document.write( "slope at every value of \"x\" is (3/2)x^(1/2)
\n" ); document.write( "gradient = slope at x = 4 is (3/2)4^(1/2) = 3
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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