document.write( "Question 1114985: ∠1 and ​ ∠2 ​ are a linear pair, and ​ ∠2 ​ and ​ ∠3 ​ are vertical angles. m∠1=(5y−8)∘ and ​ m∠2=(12+6y)∘ .\r
\n" ); document.write( "\n" ); document.write( "What is m∠3 ?\r
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\n" ); document.write( "\n" ); document.write( "16°\r
\n" ); document.write( "\n" ); document.write( "72°\r
\n" ); document.write( "\n" ); document.write( "108°\r
\n" ); document.write( "\n" ); document.write( "132° \n" ); document.write( "
Algebra.Com's Answer #729905 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
∠1 and ​ ∠2 ​ are a linear pair, and ​ ∠2 ​ and ​ ∠3 ​ are vertical angles.
\n" ); document.write( "1 + 2 = 180 degrees ; 2=3
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\n" ); document.write( "m∠1=(5y−8)∘ and ​ m∠2=(12+6y)∘
\n" ); document.write( "5y-8+12+6y = 180 degrees
\n" ); document.write( "11y+4 = 180degrees
\n" ); document.write( "11y = 176
\n" ); document.write( "y = 16
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\n" ); document.write( "What is m∠3 ?
\n" ); document.write( "m<3 = m<2 = 12+6y = 12+6*16 = 12+96 = 108 degrees
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\n" ); document.write( "16°
\n" ); document.write( "72°
\n" ); document.write( "108°
\n" ); document.write( "132°
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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