document.write( "Question 1114968: Given sin (A) = 3/5 with 0 < A < 90 and cos (B) = 4/5 with 270 < B < 360, which expression gives the value of sin(A-B)?\r
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document.write( "A. -24/25
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document.write( "B. 0
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document.write( "C. 24/25
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document.write( "D. 1 \n" );
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Algebra.Com's Answer #729883 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Using the pythagorean identity, you'll find that \n" ); document.write( "cos(A) = 4/5 \n" ); document.write( "sin(B) = -3/5 \n" ); document.write( "Note: Since B is in quadrant 4, the sine value here is negative\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, \n" ); document.write( "sin(A-B) = sin(A)*cos(B)-cos(A)*sin(B) \n" ); document.write( "sin(A-B) = (3/5)*(4/5) - (4/5)*(-3/5) \n" ); document.write( "sin(A-B) = 12/25 + 12/25 \n" ); document.write( "sin(A-B) = 24/25 \n" ); document.write( " \n" ); document.write( " |