document.write( "Question 1114944: A manager wants to assign 20 workers to four distinct construction jobs. These jobs require 6, 4, 3, and 7 workers respectively. In how many different ways can the manager assign the workers?
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Algebra.Com's Answer #729859 by math_helper(2461) $\"\"$ $\"About$

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I think it would be 20C6 * 14C4 * 10C3 * 7C7 = $\"+highlight%28+4655851200+%29++\"$ ways.
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\n" ); document.write( "It seems arbitrary to assign the group of 6 workers first, but this result is independent of which group you assign first. Even if you group, say, the 7 workers first for their job, the result is the same:\r
\n" ); document.write( "\n" ); document.write( "20C7 * 13C6 * 7C4 * 3C3 = $\"+highlight+%28+4655851200+%29+\"$ ways.
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\n" ); document.write( "Of course, more complex assignments are possible (assign job 1 to a person from group of 6, assign job 2 to a person from the group of 3, etc.), but the number of possible ways should still be the same.
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