document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114943>Question 1114943</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A baseball player has a batting average of 0.346, so the probability of a hit is 0,346. Assume that his hitting attempts are independent of each other. Assume that the batter gets up to bat 4 times in each game. Estimate the probability that in 50 consecutive games, there are at least 45 games in which the batter gets at least one hit. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729855 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729855\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> probability of no hits per game is 0.654^4=0.1829<BR>\n" );
document.write( "probability of at least one hit is 0.8171<BR>\n" );
document.write( "in 50 games, probability of 45 having at least 1 is 50C45(0.8171)^45*(0.1829)^5=0.0489 ANSWER </SPAN>\n" );
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