document.write( "Question 1114932: Assume that a simple random sample has been selected from a normally distributed population. Find the test statistic, P-value, critical value(s), and state the final conclusion.\r
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document.write( "Claim: The mean time between uses of a TV remote control by males during commercials equals 5.00 sec.
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document.write( "Sample data: n = 81, x = 5.25 sec, s = 2.80 sec. The significance level is α = 0.01. \n" );
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Algebra.Com's Answer #729848 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! The test statistic is a t (0.995,df=80) with a critical value of |t|>2.639 \n" ); document.write( "t=(xbar-mean)/s/sqrt(n) \n" ); document.write( "=(5.25-5)/(2.80/sqrt(81)) \n" ); document.write( "=0.25*9/2.80=2.25/2.80=0.80 \n" ); document.write( "this is not greater than the critical value, so there is insufficient evidence to reject Ho at the 0.01 level or to say the value of 5 seconds is not correct. p-value is 0.42. \n" ); document.write( " |