document.write( "Question 1114915: solve: (abs(x-1))^(x^2+3x)=(abs(x-1))^(5-x). Abs means Absolute \n" ); document.write( "
Algebra.Com's Answer #729825 by ikleyn(52787)\"\" \"About 
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document.write( "\"abs%28x-1%29%5E%28x%5E2%2B3x%29\" = \"abs%28x-1%29%5E%285-x%29\"  ====>  \r\n" );
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document.write( "x^2 + 3x = 5 - x  ====>\r\n" );
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document.write( "x^2 + 4x - 5 = 0\r\n" );
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document.write( "(x+5)*(x-1) = 0\r\n" );
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document.write( "The roots are  x= -5  and  x= 1.\r\n" );
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document.write( "Both the roots satisfy the original equation.\r\n" );
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document.write( "Answer.  The solutions are  x= -5  and  x= 1.\r\n" );
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