document.write( "Question 1114897: Hi
\n" ); document.write( "elaine went shopping.she spent 62 dollars in one shop and 3/4 of the remainder of her money in another. If she had 70 dollars left. How much did she have at first. \r
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Algebra.Com's Answer #729818 by ankor@dixie-net.com(22740)\"\" \"About 
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she spent 62 dollars in one shop and 3/4 of the remainder of her money in another.
\n" ); document.write( " If she had 70 dollars left.
\n" ); document.write( " How much did she have at first.
\n" ); document.write( ":
\n" ); document.write( "let x = amt she had at first
\n" ); document.write( "x - 62 - \"3%2F4\"(x-62) = 70
\n" ); document.write( "x - \"3%2F4\"(x-62) = 70 + 62
\n" ); document.write( "x - \"3%2F4\"(x-62) = 132
\n" ); document.write( "multiply equation by 4, to get rid of the denominator
\n" ); document.write( "4x -3(x-62) = 4(132)
\n" ); document.write( "4x - 3x + 186 = 528
\n" ); document.write( "x = 528 - 186
\n" ); document.write( "x = $342 is amt she had at first
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "see if that checks out
\n" ); document.write( "342 - 62 -\"3%2F4\"(342-62) =
\n" ); document.write( "280 - \"3%2F4\"(280) =
\n" ); document.write( "280 - 210 = 70\r
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\n" ); document.write( "\n" ); document.write( "x
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