document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114865>Question 1114865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Quick Check in Special Right Triangles:<BR>\n" );
document.write( "5. An equilateral triangle has an altitude of 15 m. What is the perimeter of that triangle?<BR>\n" );
document.write( "A) 30 square root 2 m<BR>\n" );
document.write( "B) 45 m<BR>\n" );
document.write( "C) 30 square root 3 m<BR>\n" );
document.write( "D) 60 square root 3 m </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729783 by </B><A HREF=/tutors/aboutme.mpl?userid=math_helper><B>math_helper(2461)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_helper><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=math_helper><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729783\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One way the side can be found is by  sin(60) = 15/s   —>  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+s+=+10%2Asqrt%283%29+ ALIGN=MIDDLE  ALT=\"+s+=+10%2Asqrt%283%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > m \r<BR>\n" );
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document.write( "The perimeter is 3 times that:  <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+highlight%28++30%2Asqrt%283%29+%29+ ALIGN=MIDDLE  ALT=\"+highlight%28++30%2Asqrt%283%29+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > m </SPAN>\n" );
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