document.write( "Question 1114839: A company that conducts bus tours found that when the price was $9.00 per person,the average number of customers was 1000 per week. When the company reduced the price to $7.00 per person, the average number of customers increased to 1500 per week.
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document.write( "(a)Write a linear equation that gives the unit price p, in terms of the average number of customers x per week. (Write your answer in the form p = mx + b.)
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document.write( "b). What unit price should be charged to obtain the greatest weekly revenue? \n" );
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Algebra.Com's Answer #729767 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A company that conducts bus tours found that when the price was $9.00 per person,the average number of customers was 1000 per week. When the company reduced the price to $7.00 per person, the average number of customers increased to 1500 per week. \n" ); document.write( "(a)Write a linear equation that gives the unit price p, in terms of the average number of customers x per week. (Write your answer in the form p = mx + b.) \n" ); document.write( "b). What unit price should be charged to obtain the greatest weekly revenue? \n" ); document.write( "------ \n" ); document.write( "Revenue = price*# of customers \n" ); document.write( "$2 decrease in price resulted in 500 increase in customers \n" ); document.write( "R(x) = (9-2x)(1000+500x) \n" ); document.write( "----- \n" ); document.write( "To find \"greatest weekly revenue\":: \n" ); document.write( "R(x) = 9000 + 4500x-2000x -1000x^2 \n" ); document.write( "R'(x) = 2500 - 2000x \n" ); document.write( "Solve:: -2000x = -2500 \n" ); document.write( "x = 1.25 \n" ); document.write( "Ans: Best price $9-2*1.25 = $6.50 \n" ); document.write( "------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------------- \n" ); document.write( " |