document.write( "Question 1114839: A company that conducts bus tours found that when the price was $9.00 per person,the average number of customers was 1000 per week. When the company reduced the price to $7.00 per person, the average number of customers increased to 1500 per week.
\n" ); document.write( "(a)Write a linear equation that gives the unit price p, in terms of the average number of customers x per week. (Write your answer in the form p = mx + b.)
\n" ); document.write( "b). What unit price should be charged to obtain the greatest weekly revenue?
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Algebra.Com's Answer #729767 by stanbon(75887)\"\" \"About 
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A company that conducts bus tours found that when the price was $9.00 per person,the average number of customers was 1000 per week. When the company reduced the price to $7.00 per person, the average number of customers increased to 1500 per week.
\n" ); document.write( "(a)Write a linear equation that gives the unit price p, in terms of the average number of customers x per week. (Write your answer in the form p = mx + b.)
\n" ); document.write( "b). What unit price should be charged to obtain the greatest weekly revenue?
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\n" ); document.write( "Revenue = price*# of customers
\n" ); document.write( "$2 decrease in price resulted in 500 increase in customers
\n" ); document.write( "R(x) = (9-2x)(1000+500x)
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\n" ); document.write( "To find \"greatest weekly revenue\"::
\n" ); document.write( "R(x) = 9000 + 4500x-2000x -1000x^2
\n" ); document.write( "R'(x) = 2500 - 2000x
\n" ); document.write( "Solve:: -2000x = -2500
\n" ); document.write( "x = 1.25
\n" ); document.write( "Ans: Best price $9-2*1.25 = $6.50
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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