document.write( "Question 100153: Geomatry. The length of a rectangle is 1 cm longer than its width. If the diagnonal of the rectangle is 4cm what are the dimensions (the length and teh width) of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #72975 by oberobic(2304)![]() ![]() ![]() You can put this solution on YOUR website! The statement that the \"length is 1 cm longer than the width\" means that we can define the length (l) = w + 1. Width (w) is simply = to w. So, the rectangle has sides of w, w+1, w, and w+1. The diagonal is known to be 4 cm (given).\r \n" ); document.write( "\n" ); document.write( "Now we simply apply the Pythagorean formula. Let's call the diagonal d. That means \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Therefore, \n" ); document.write( "\n" ); document.write( "Of course, \n" ); document.write( "\n" ); document.write( "Substituting what we know:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Subtracting 16 from both sides:\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This does not factor easily, so you can use the quadratic equation to find w.\r \n" ); document.write( "\n" ); document.write( "Quadratic formula: \n" ); document.write( "\n" ); document.write( "Substituing, we have |