document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114764>Question 1114764</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have a triangle. A bisector divides one of its angles into two parts. The side divided into two parts - one part is x and total of two parts is 8. One of the other two sides is 5 and the other is 7. find the x.\r<BR>\n" );
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document.write( "If i couldn’t explain my problem very well you can type angle bisector theorem practice in google and click what came out the first. I am stuck in the 4th problem.<BR>\n" );
document.write( "Thanks in advance. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729675 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the angle bisector divides the side of the triangle, proportionally <BR>\n" );
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document.write( "5/x = 7/(8-x)<BR>\n" );
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document.write( "cross multiply the fractions<BR>\n" );
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document.write( "5(8-x) = 7x<BR>\n" );
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document.write( "40 -5x = 7x<BR>\n" );
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document.write( "12x = 40<BR>\n" );
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document.write( "x = 40/12 = 10/3<BR>\n" );
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document.write( "answer is 3 and 1/3<BR>\n" );
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