document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114722>Question 1114722</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you decide to make homemade dried apricots and purchased 10 pounds of fresh apricots at the farmer's market. when the apricots were fresh, 85% of their weight was water. after 12 hours of drying in your excalibur dehydrator, a test showed that the water content of the apricots was now 25% by weight. how many pounds did the apricots weigh after 12 hours in the dehydrator </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729627 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729627\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Put attention on the concentrations of water.\r<BR>\n" );
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document.write( "If Q is quantity of water removed, as pounds,<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2810%2A0.85-Q%29%2F%2810-Q%29=0.25 ALIGN=MIDDLE  ALT=\"%2810%2A0.85-Q%29%2F%2810-Q%29=0.25\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=Q=8 ALIGN=MIDDLE  ALT=\"Q=8\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "The original 10 pounds fresh apricots became 2 pounds after DRYING to 25% water. </SPAN>\n" );
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