document.write( "Question 1114704: A remote-controlled boat can travel at 4 feet per second in calm water. For a specific trip, the boat traveled 48 feet with the current, and then it traveled 16 feet against the current in the same amount of time. How fast is the current? \n" ); document.write( "
Algebra.Com's Answer #729611 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! distance=rate*time; rate= speed of boat (b)+ speed of current (c) or 4+c down stream and 4-c upstream \n" ); document.write( "48=(4+c)* time \n" ); document.write( "16=(4-c)*time\r \n" ); document.write( "\n" ); document.write( "time is the same \n" ); document.write( "time=48/(4+c) \n" ); document.write( "time=16/(4-c) \n" ); document.write( "set the two equal.\r \n" ); document.write( "\n" ); document.write( "48/(4+c)=16/(4-c) \n" ); document.write( "cross-multiply \n" ); document.write( "192-48c=64+16c \n" ); document.write( "64c=128 \n" ); document.write( "c=2 feet per second ANSWER \n" ); document.write( "boat goes 6 ft/sec downstream and takes 8 seconds to go 48 feet \n" ); document.write( "boat goes 2 ft/sec upstream and takes 8 seconds to go 16 feet \n" ); document.write( " |