document.write( "Question 1114531: Find the scalar and vector products of the vectors A and B, where A = 2i + j + k and B = 4i + 2j - 3k, also find the angle between A and B \n" ); document.write( "

Algebra.Com's Answer #729528 by Alan3354(69443) $\"\"$ $\"About$

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Find the scalar and vector products of the vectors A and B, where
\n" ); document.write( "A = 2i + j + k and
\n" ); document.write( "B = 4i + 2j - 3k, also find the angle between A and B
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\n" ); document.write( "Scalar or dot product = 2*4 + 1*2 + 1*-3 = 7
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\n" ); document.write( "The cosine of the angle is the dot product over the magnitude product.
\n" ); document.write( "cos(t) = (A dot B)/(|A|*|B|)
\n" ); document.write( "|A| = sqrt(2^2 + 1^1 + 1^2) = sqrt(6)
\n" ); document.write( "|B| = sqrt(4^2 + 2^2 + 3^2) = sqrt(29)
\n" ); document.write( "cos = 7/sqrt(6*29)
\n" ); document.write( "Angle =~ 57.95º
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\n" ); document.write( "Vector or Cross Product:
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document.write( "|i   j   k|\r\n" );
document.write( "|2   1   1| = i*(-3-2) - j*(-6-4) + k*(4-4) = -5i + 10j\r\n" );
document.write( "|4   2  -3|\r\n" );
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\n" ); document.write( "= -5i + 10j \n" ); document.write( "

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