document.write( "Question 1114481: Claudia can run 60 yards in 15 seconds. Valerie can run the same distance in 20 seconds. If Valerie is 20 yards ahead of Claudia when they both start running, how long does it take for Claudia to catch Valerie? \n" ); document.write( "

Algebra.Com's Answer #729424 by ikleyn(52778) $\"\"$ $\"About$

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document.write( "Claudia's rate is  = 4 yards per second.\r\n" );
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document.write( "Valeria's rate is  = 3 yards per second.\r\n" );
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document.write( "If t is the time after their start, then the Claudia's position is 4t yards from the start, \r\n" );
document.write( "     while Valeria's position is  (3t + 20) yards from the same point.\r\n" );
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document.write( "At the catching up moment the distances are the same:\r\n" );
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document.write( "4t = 3t + 20,   or\r\n" );
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document.write( "4t - 3t = 20  ====>  t = 20 seconds.\r\n" );
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document.write( "Answer.  Claudia will catch up Valeria in 20 seconds.\r\n" );
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\n" ); document.write( "\n" ); document.write( "---------------
\n" ); document.write( "See introductory lessons on Travel and Distance problems\r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in opposite directions \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in the same direction (catching up)\r
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\n" ); document.write( "\n" ); document.write( "They are written specially for you.\r
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\n" ); document.write( "\n" ); document.write( "You will find the solutions of many similar problems there.\r
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\n" ); document.write( "\n" ); document.write( "Read them and learn once for all from these lessons on how to solve simple Travel and Distance problems.\r
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\n" ); document.write( "\n" ); document.write( "Become an expert in this area.\r
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