document.write( "Question 100161: Each of two congruent sides of a isosceles triangle is 8in less than twice the base. The perimeter of the triangle is 74in What is the length of the base? \n" ); document.write( "
Algebra.Com's Answer #72942 by checkley71(8403)\"\" \"About 
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X=BASE MEASUREMENT.
\n" ); document.write( "SIDE=2X-8.
\n" ); document.write( "X+(2X-8)+(2X-8)=74
\n" ); document.write( "5X-16=74
\n" ); document.write( "5X=74+16
\n" ); document.write( "5X=90
\n" ); document.write( "X=90/5
\n" ); document.write( "X=18 IS THE LENGTH OF THE BASE.
\n" ); document.write( "2*18-8=36-8=28 FOR THE SIDES
\n" ); document.write( "PROOF
\n" ); document.write( "18+2*28=18+56=74
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