document.write( "Question 1114419: The perimeter of a rectangular city lot was 420 feet. The lot was divided into two equal lots having the same width and half the length of the original lot. Find the dimensions of the smaller lots if their perimeters were 260 feet each. \n" ); document.write( "
Algebra.Com's Answer #729370 by Fombitz(32388)\"\" \"About 
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\n" ); document.write( "Originally,
\n" ); document.write( "\"2L%2B2L%2BW%2BW=420\"
\n" ); document.write( "\"4L%2B2W=420\"
\n" ); document.write( "1.\"2L%2BW=210\"
\n" ); document.write( "Then after the split,
\n" ); document.write( "\"2L%2B2W=260\"
\n" ); document.write( "2.\"L%2BW=130\"
\n" ); document.write( "Subtracting 2 from 1,
\n" ); document.write( "\"2L%2BW-L-W=210-130\"
\n" ); document.write( "\"L=80\"\"ft\"
\n" ); document.write( "Now use either equation to solve for W.
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