document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114336>Question 1114336</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemical supply company ships a certain solvent in 10-gallon drums. Let X represent the number of drums ordered by a randomly chosen customer. Assume X has the following probability mass function:<BR>\n" );
document.write( "x           1     2      3     4      5<BR>\n" );
document.write( "p(x)       0.33   0.2   0.2   0.17    0.1\r<BR>\n" );
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document.write( "Find the standard deviation of the number of drums ordered.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729301 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729301\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The mean is x*p(x)=<BR>\n" );
document.write( "0.33+0.4+0.6+0.68+0.5=2.51<BR>\n" );
document.write( "The variance is sum (x-expected value or mean^2)*p(x)<BR>\n" );
document.write( "(-1.51)^2*0.33+(2-2.51)^2*0.2+(3-2.51)^2*0.2+(4-2.51)^2*0.17+(5-2.51)^2*0.1=<BR>\n" );
document.write( "0.752+0.052+0.048+0.377+0.620=1.849<BR>\n" );
document.write( "sd is sqrt(1.849)=1.36 ANSWER<BR>\n" );
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