document.write( "Question 1114309: Two gears rotate so that one completes 1 more revolution per minute than the other. If it takes the smaller gear 1 second less than the larger gear to complete 1/5 revolution, how many revolutions does each gear make in 1 minute? \n" ); document.write( "
Algebra.Com's Answer #729300 by ikleyn(52787)\"\" \"About 
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document.write( "Answer.  Faster gear makes 4 revolutions per minute, while the slower gear makes 3 revolutions per minute.\r\n" );
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document.write( "Check.  The faster gear makes one revolution in 60/4 = 15 seconds.\r\n" );
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document.write( "        The slower gear makes one revolution in 60/3 = 20 seconds.\r\n" );
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document.write( "        Difference of times to make 1/5 revolution is  (20-15)/5 = 1 second.\r\n" );
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document.write( "Let n be the number of rotations of the faster gear per minute.\r\n" );
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document.write( "Then the number of rotations of the slower gear per minute is (n-1),  according to the condition.\r\n" );
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document.write( "The time to make one rotation for faster gear is  \"1%2Fn\"  of an minute for the faster gear  and  \"1%2F%28n-1%29\"  of an minute for the slower gear.\r\n" );
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document.write( "The difference  \"1%2F%28n-1%29\" - \"1%2Fn\"  is equal to 5 seconds,  or  \"5%2F60\"  of the minute,  according to the condition.\r\n" );
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document.write( "So, the equation is\r\n" );
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document.write( "\"1%2F%28n-1%29\" - \"1%2Fn\" = \"5%2F60\",\r\n" );
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document.write( "and when you solve it, you will get the answer claimed above.\r\n" );
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