document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14514>Question 14514</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the following information to solve questions 1-3.  Right triangle ABC has one leg of length 3 in. and a hypotenuse of length 5 in.  Find the length of the other leg\r<BR>\n" );
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document.write( "Question 2\r<BR>\n" );
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document.write( "Find the perimeter of the triangle\r<BR>\n" );
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document.write( "Question 3\r<BR>\n" );
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document.write( "Find the area of the triangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7293 by </B><A HREF=/tutors/aboutme.mpl?userid=Starz><B>Starz(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Starz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7293\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> alright....let's get down to work\r<BR>\n" );
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document.write( "you have the hypotenuse and a length, so to get the other length you have to use this equation:\r<BR>\n" );
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document.write( "(5 in. x 5 in.)- (3 in. x 3 in.)= unknown length x unknown length<BR>\n" );
document.write( "25-9<BR>\n" );
document.write( "16\r<BR>\n" );
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document.write( "the squareroot of 16 is 4....so the unknown length is 4.\r<BR>\n" );
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document.write( "Now add everything to get the perimeter. 5+3+4=12 inches\r<BR>\n" );
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document.write( "For the area use this equation:\r<BR>\n" );
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document.write( "base x length divided by two<BR>\n" );
document.write( "3 x 4 divided by 2<BR>\n" );
document.write( "12 divided by 2<BR>\n" );
document.write( "6...the area is 6 inches squared </SPAN>\n" );
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