document.write( "Question 1114331: How many different 5 digit numbers can be formed from the digit 1,2,3,4 and 5 if
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document.write( "(i). There are no restrictions on the digit and repetitions are allowed.
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document.write( "(ii). The number is odd and no repetition is allowed.
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document.write( "(iii).The number is even and reputation are allowed.
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document.write( "(iv). The number is greater than 50,000 and no repetitions are allowed. \n" );
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Algebra.Com's Answer #729294 by Edwin McCravy(20055)![]() ![]() You can put this solution on YOUR website! How many different 5 digit numbers can be formed \n" ); document.write( "from the digit 1,2,3,4 and 5 if \r \n" ); document.write( "\n" ); document.write( "(i). They are no restrictions on the digit and repetitions are allowed. Choose the 1st digit 5 ways.\r\n" ); document.write( "Choose the 2nd digit 5 ways.\r\n" ); document.write( "Choose the 3rd digit 5 ways.\r\n" ); document.write( "Choose the 4th digit 5 ways.\r\n" ); document.write( "Choose the 5th digit 5 ways.\r\n" ); document.write( "\r\n" ); document.write( "5×5×5×5×5 = 55 = 3125 ways(ii). The number is odd and no repetitions are allowed. Choose the 5th digit 3 ways. (either 1,3, or 5)\r\n" ); document.write( "Choose the 1st digit 4 ways.\r\n" ); document.write( "Choose the 2nd digit 3 ways.\r\n" ); document.write( "Choose the 3rd digit 2 ways.\r\n" ); document.write( "Choose the 4th digit 1 way.\r\n" ); document.write( "\r\n" ); document.write( "3×4×3×2×1 = 72 ways(iii).The number is even and reputations are allowed. Choose the 5th digit 2 ways. (either 2 or 4)\r\n" ); document.write( "Choose the 1st digit 5 ways.\r\n" ); document.write( "Choose the 2nd digit 5 ways.\r\n" ); document.write( "Choose the 3rd digit 5 ways.\r\n" ); document.write( "Choose the 4th digit 5 ways.\r\n" ); document.write( "\r\n" ); document.write( "2×5×5×5×5 = 2×54 = 1250 ways(iv). The number is greater than 50 000 and no repetitions are allowed Choose the 1st digit 1 way. (as 5)\r\n" ); document.write( "Choose the 2nd digit 4 ways.\r\n" ); document.write( "Choose the 3rd digit 3 ways.\r\n" ); document.write( "Choose the 4th digit 2 ways.\r\n" ); document.write( "Choose the 5th digit 1 way.\r\n" ); document.write( "\r\n" ); document.write( "1×4×3×2×1 = 60 ways\r\n" ); document.write( "\r\n" ); document.write( "Edwin\n" ); document.write( " |