document.write( "Question 100138This question is from textbook Glenco Algebra I
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document.write( ": The Yankee Clipper leaves the pier at 9:00 AM at 8 knots. A half hour later, The River Rover leaves the same pier in the same direction traveling at 10 knots. At what time will The River Rover overtake The Yankee Clipper?\r
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document.write( "I'm not sure how to solve this when both time and distance are missing. Thanks. \n" );
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Algebra.Com's Answer #72926 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The Yankee Clipper leaves the pier at 9:00 AM at 8 knots. A half hour later, The River Rover leaves the same pier in the same direction traveling at 10 knots. At what time will The River Rover overtake The Yankee Clipper? \n" ); document.write( "--------------- \n" ); document.write( "Comment: That is what algebra is all about; if something is missing, \n" ); document.write( "call it \"x\" and solve for it. \n" ); document.write( "------------------------- \n" ); document.write( "Clipper DATA: \n" ); document.write( "Rate = 8 knots ; Distance = x miles ; time = d/r = x/8 hrs. \n" ); document.write( "----------------- \n" ); document.write( "Rover DATA: \n" ); document.write( "Rate = 10 knots; Distance = x miles ; time = d/r = x/10 hrs. \n" ); document.write( "----------------- \n" ); document.write( "EQUATION: \n" ); document.write( "Cipper time = Rover time + (1/2) hr. \n" ); document.write( "x/8 = x/10 + (1/2) \n" ); document.write( "Multiply thru by 40 to get: \n" ); document.write( "5x = 4x + 20 \n" ); document.write( "x = 20 miles \n" ); document.write( "Clipper time = 20/8= 5/2 hrs. \n" ); document.write( "9:00 plus (5/2) hrs = 11:30 AM \n" ); document.write( "Rover will over take Clipper at 11:30 AM \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |