document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114249>Question 1114249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One number is nine more than twice another. If their sum is decreased by ten, the result is eleven. Find the numbers.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729240 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729240\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> lET THE NUMBERS BE X & Y\r<BR>\n" );
document.write( "\n" );
document.write( "X=2Y +9<BR>\n" );
document.write( "X-2Y=9\r<BR>\n" );
document.write( "\n" );
document.write( "X+Y-10=11<BR>\n" );
document.write( "X+Y=21\r<BR>\n" );
document.write( "\n" );
document.write( "X-2Y=9<BR>\n" );
document.write( "X+Y=21<BR>\n" );
document.write( "SUBTRACT THE EQUATIONS\r<BR>\n" );
document.write( "\n" );
document.write( "-3Y=-12<BR>\n" );
document.write( "Y=4\r<BR>\n" );
document.write( "\n" );
document.write( "X=2Y+9<BR>\n" );
document.write( "X=2*4+9<BR>\n" );
document.write( "X=17\r<BR>\n" );
document.write( "\n" );
document.write( "17 AND 4 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );