document.write( "Question 1114184: A box contains $6.15 in nickels , dimes, and quarters. There are 36 coins in all, and the sum of the numbers of nickels and dimes
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Algebra.Com's Answer #729199 by MathTherapy(10552) $\"\"$ $\"About$

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A box contains $6.15 in nickels , dimes, and quarters. There are 36 coins in all, and the sum of the numbers of nickels and dimes
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Let the number of nickels, dimes, and quarters be N, D, and Q, respectively
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document.write( "Then we get: .05N + .1D + .25Q = 6.15 ------ eq (i)
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document.write( "Also, N + D + Q = 36 ------- eq (ii)
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document.write( "In addition, N + D = Q - 2______N + D - Q = - 2 ------ eq (iii)
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document.write( "2Q = 38 ------ Subtracting eq (iii) from eq (ii)
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document.write( ".05N + .1D + .25(19) = 6.15 ------ Substituting 19 for Q in eq (i)
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document.write( ".05N + .1D + 4.75 = 6.15
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document.write( ".05N + .1D = 1.4 ------- eq (iv)\r
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document.write( "N + D = 19 - 2 ------- Substituting 19 for Q in eq (iii)
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document.write( "N + D = 17 ------ eq (v)
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document.write( "- .1N - .1D = - 1.7 ------- Multiplying eq (v) by - .1 ------ eq (vi)
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document.write( "- .05N = - .3 ------ Adding eqs (vi) & (iv)
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document.write( "6 + D = 17 ------ Substituting 6 for N in eq (v)
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