document.write( "Question 1114108: A single-engine plane and a commercial jet leave an airport at 10 A.M. and head for an airport 930 mi away. The rate of the jet is four times the rate of the single engine plane. The single-engine plane arrives 5 h after the jet. Find the rate of each plane \n" ); document.write( "
Algebra.Com's Answer #729126 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A single-engine plane and a commercial jet leave an airport at 10 A.M. and head for an airport 930 mi away. \n" ); document.write( " The rate of the jet is four times the rate of the single engine plane. \n" ); document.write( " The single-engine plane arrives 5 h after the jet. \n" ); document.write( " Find the rate of each plane \n" ); document.write( ": \n" ); document.write( "let s = the speed of the prop plane \n" ); document.write( "then \n" ); document.write( "4s = the speed of the jet \n" ); document.write( ": \n" ); document.write( "Write a time equation; time = dist/speed \n" ); document.write( "Prop time - jet time = 5 hrs \n" ); document.write( " \n" ); document.write( "multiply equation by 4s, cancel the denominators and we have: \n" ); document.write( "4(930) - 930 = 5(4s) \n" ); document.write( "3720 - 930 = 20s \n" ); document.write( "2790 = 20s \n" ); document.write( "s = 2790/20 \n" ); document.write( "s = 139.5 mph is the prop plane \n" ); document.write( "then \n" ); document.write( "4(139.5) = 558 mph is jets speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the actual time of each \n" ); document.write( "930/139.5 = 6 \n" ); document.write( "930/558 = 1 \n" ); document.write( "----------------------------- \n" ); document.write( "travel time dif: 5 hrs \n" ); document.write( " |