document.write( "Question 1114110: Solve \"Solve+\"(9/16)^(2-x)=(64/27)^x \n" ); document.write( "
Algebra.Com's Answer #729122 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Note that \"9%2F16+=+%283%2F4%29%5E2\" and \"64%2F27+=+%284%2F3%29%5E3\".

\n" ); document.write( "To solve the equation, we want to make the fractions the same. So rewrite \"%284%2F3%29%5E3\" as \"%283%2F4%29%5E%28-3%29\".

\n" ); document.write( "Then

\n" ); document.write( "\"%289%2F16%29%5E%282-x%29=%2864%2F27%29%5Ex\"
\n" ); document.write( "\"%28%283%2F4%29%5E2%29%5E%282-x%29+=+%28%28%283%2F4%29%5E-3%29%5Ex%29%29\"
\n" ); document.write( "\"%283%2F4%29%5E%284-2x%29+=+%283%2F4%29%5E%28-3x%29\"
\n" ); document.write( "\"4-2x+=+-3x\"
\n" ); document.write( "\"x+=+-4\"
\n" ); document.write( "
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