document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114086>Question 1114086</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Janet spent $42 on shoes, this was $14 less than twice the cost of a blouse.  Let the variable 'p' be the cost of the shoes.  Give an algebraic equation for the cost of the blouse and solve the equation </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729118 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729118\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i believe your algebraic equation will be:\r<BR>\n" );
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document.write( "p = 2b - 14\r<BR>\n" );
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document.write( "when p = 42, this equation becomes 42 = 2b - 14\r<BR>\n" );
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document.write( "add 14 to both sides of the equation to get 56 = 2b\r<BR>\n" );
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document.write( "solve for b to get b = 56/2 = 28\r<BR>\n" );
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