document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1114099>Question 1114099</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The weight that can be safely supported by a 2-by 6-inch support beam varies inversely with its length. A builder finds that a support beam that is 10 feet long will support 800 pounds. Find the weight that can be safely supported by a beam that is 16 feet long.\r<BR>\n" );
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document.write( "The weight that can be safely supported by the beam is _ lb. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729109 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729109\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The weight that can be safely supported by a 2-by 6-inch support beam varies inversely with its length. A builder finds that a support beam that is 10 feet long will support 800 pounds. Find the weight that can be safely supported by a beam that is 16 feet long.<BR>\n" );
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document.write( "w = k/L<BR>\n" );
document.write( "800 = k/10<BR>\n" );
document.write( "k = 8000<BR>\n" );
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document.write( "w = 8000/L<BR>\n" );
document.write( "w = 8000/16<BR>\n" );
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document.write( "w = 500 lbs<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( "The weight that can be safely supported by the beam is 500 lb.  </SPAN>\n" );
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