document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14563>Question 14563</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mrs. Brook lacks 7 years from being 5 times as old as her son.  Six years from now she will lack 3 years from being three times as old as her son is then. Find each of their ages. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7291 by </B><A HREF=/tutors/aboutme.mpl?userid=Starz><B>Starz(4)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Starz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7291\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let's see...we can work this out with an equation\r<BR>\n" );
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document.write( "let x represent the age of her son\r<BR>\n" );
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document.write( "5x-7=3x-3+6\r<BR>\n" );
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document.write( "now....let's solve\r<BR>\n" );
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document.write( "5x-7=3x-3+6<BR>\n" );
document.write( "5x=3x-3+6+7<BR>\n" );
document.write( "5x=3x+16<BR>\n" );
document.write( "5x-3x=16<BR>\n" );
document.write( "2x=16<BR>\n" );
document.write( "x=16/2<BR>\n" );
document.write( "x=8\r<BR>\n" );
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document.write( "Now that you have the son's age, you can find out mrs. brook's age.\r<BR>\n" );
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document.write( "5 x 8-7<BR>\n" );
document.write( "40-7<BR>\n" );
document.write( "33\r<BR>\n" );
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document.write( "Therefore, her son is 8 and she is 33. </SPAN>\n" );
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