document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1113987>Question 1113987</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Suppose Tom has 17 coins totaling $2.60. If he has only dimes and quarters, how many of each type does he have? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #729018 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=729018\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d + q = 17 subtract q from both sides:<BR>\n" );
document.write( "d = 17 - q We'll use this value for d below:<BR>\n" );
document.write( "0.10d + 0.25q = 2.60<BR>\n" );
document.write( "0.10(17-q) + 0.25q = 2.60<BR>\n" );
document.write( "1.7 - 0.10q + 0.25q = 2.60<BR>\n" );
document.write( "0.15q = 0.9<BR>\n" );
document.write( "q = 0.9/0.15 = 6 he has 6 quarters<BR>\n" );
document.write( "d = 17- 6 = 11 he has 11 dimes<BR>\n" );
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document.write( "check:<BR>\n" );
document.write( "6(0.25) + 11(0.10) = 2.60<BR>\n" );
document.write( "1.5 + 1.10 = 2.60 Correct </SPAN>\n" );
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