document.write( "Question 1113943: The half-life of a particular radioactive isotope is 72 hours.\r
\n" ); document.write( "\n" ); document.write( "Write an equation to relate the mass of radioactive material remaining to time (in hours).\r
\n" ); document.write( "\n" ); document.write( "Starting with 170g, what mass will remain in 3 weeks?\r
\n" ); document.write( "\n" ); document.write( "If after one day (24 hours), a different sample of the material was found to have a mass of 14 mg with a half-life of 12h, what was the initial mass of the sample?\r
\n" ); document.write( "\n" ); document.write( "solve using log if possible
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Algebra.Com's Answer #728987 by josgarithmetic(39618)\"\" \"About 
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\n" ); document.write( "The half-life of a particular radioactive isotope is 72 hours.
\n" ); document.write( "Write an equation to relate the mass of radioactive material remaining to time (in hours).
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\n" ); document.write( "\n" ); document.write( "\"y=pe%5E%28-kt%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28y%29=ln%28p%29%2Bln%28e%5E%28-kt%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28y%29=ln%28p%29-kt\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%28y%29-ln%28p%29=-kt\"\r
\n" ); document.write( "\n" ); document.write( "\"kt=ln%28p%29-ln%28y%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"k=%281%2Ft%29%28ln%28p%2Fy%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "If half life is 72 hours, then \"k=%281%2F72%29%2Aln%282%29\"\r
\n" ); document.write( "\n" ); document.write( "\"k=0.009627\"\r
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\n" ); document.write( "\n" ); document.write( "This model then becomes \"highlight%28y=p%2Ae%5E%28-0.009627t%29%29\"
\n" ); document.write( "p, initial quantity
\n" ); document.write( "y, final quantity
\n" ); document.write( "t, time in hours\r
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\n" ); document.write( "\n" ); document.write( "You can figure the other questions based on that.
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