document.write( "Question 840522: An object is projected vertically upward from the top of a building with an initial velocity of 96 ft/sec. Its distance s(t) in feet above the ground after t seconds is given by the equation
\n" ); document.write( "s(t) = −16t2 + 96t + 120.
\n" ); document.write( "(a) Find its maximum distance above the ground.
\n" ); document.write( "s(t) = ft\r
\n" ); document.write( "\n" ); document.write( "(b) Find the height of the building.
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Algebra.Com's Answer #728981 by amalm06(224)\"\" \"About 
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The velocity of the object is given by \"v%28t%29=-32t%2B96\"\r
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\n" ); document.write( "\n" ); document.write( "The maximum distance above the ground occurs when the velocity of the ball is 0.\r
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\n" ); document.write( "\n" ); document.write( "-32t+96=0, therefore t=3. The object reaches its maximum height after 3 s.\r
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\n" ); document.write( "\n" ); document.write( "a)\"+s%283%29=%28-16%29%289%29%2B288%2B120=264+ft\" (Answer)\r
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\n" ); document.write( "\n" ); document.write( "For b), the ball is at the top of the building at time t=0.\r
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\n" ); document.write( "\n" ); document.write( "\"s%280%29=0%2B0%2B120=120+ft\" (Answer)
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