document.write( "Question 1113941: If y varies inversely with the square of x and y=9 when x=2, find y when x=0.1 \n" ); document.write( "

Algebra.Com's Answer #728975 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "If $\"y\"$ varies $\"inversely\"$ with the $\"square\"$ of $\"x\"$ :\r
\n" ); document.write( "\n" ); document.write( " $\"y=k%2Fx%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " and if $\"y=9\"$ when $\"x=2\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"9=k%2F2%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"9=k%2F4\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"9%2A4=k\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"k=36\"$ \r
\n" ); document.write( "\n" ); document.write( " find $\"y\"$ when $\"x=0.1\"$ :\r
\n" ); document.write( "\n" ); document.write( " $\"y=36%2F0.1%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=36%2F0.01\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"y=3600\"$ \r
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