document.write( "Question 1113857: Anthony is 3 times older than Marry. In 3 years he will be only twice as old as her.
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document.write( "Find their ages \n" );
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Algebra.Com's Answer #728940 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! The problem is, some of the people that write the problems don't know what they're talking about. \n" ); document.write( "----- \n" ); document.write( "1 time older = a 100% increase = 2x as old, etc. \n" ); document.write( "=============== \n" ); document.write( "PS there is no \"3 times younger\" since 1 time younger = zero. \n" ); document.write( "Same for 3 times smaller, 10 times closer, etc. \n" ); document.write( "------------ \n" ); document.write( "If the stated problem is faulty, it's not up to us or others to try to figure out what the author might have meant. \n" ); document.write( " \n" ); document.write( " |